Question

Помогите упростить 6 б, пожалуйста.

Answer 1

$sqrt{29+4sqrt7}+ frac{27}{1+2sqrt7} =sqrt{1+28+2sqrt{28}}+ frac{27}{1+2sqrt7} =\\=sqrt{(1+sqrt{28})^2}+frac{27}{1+2sqrt7}=|1+sqrt{28}|+frac{27}{1+2sqrt7}=\\=1+2sqrt7+frac{27}{1+2sqrt7}= frac{(1+2sqrt7)^2+27}{1+2sqrt7} = frac{1+4sqrt7+28+27}{1+2sqrt7} =\\= frac{56+4sqrt7}{1+2sqrt7} = frac{4(14+sqrt7)}{1+2sqrt7}$