Предмет: Физика, автор: simarin8175

Мяч брошен вертикально вверх со скоростью 24 м/с. На какую максимальную высоту он поднимется? Чему равно время подъема на максимальную высоту?

Ответы

Автор ответа: Vadim777200

0

0=V0-gt =>V0=gt => t=V0/g . H=V0t-(gt^2)/2 подставляем V0. Получается H=(gt^2)/2. Получается t=2,4 с ,а максимальная высота H=28,8 м

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