Предмет: Алгебра, автор: alfiramagzomov

Срочно пожалуйста
1) Теңдеуді шеш:(уравнение)1+sin²x=cos²x+sinx
2)tg(п/8-х3)=0
3)ctg(3п2-3х)-tgx=0
4)cos(п3+х)=0

Ответы

Автор ответа: Айнура1985

0

1+sin2x=1-sin2x+sinx
2sin2x-sinx=0
sinx(2sinx-1)=0
sinx=0
x=nп
sinx=1/2
x=(-1)k*п/6+пn

Автор ответа: alfiramagzomov

0

а остальные можете решить ?

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