Question

2x(x−3)^2−x^2(x−3)=0
x1=
x2=
x3=
Решите уравнение

Answer 1

2x(x-3)²-x²(x-3)=0
2x(x²-6x+9)-x³+3x²=0
2x³-12x²+18x-x³+3x²=0
x³-9x²+18x=0
x(x²-9x+18)=0
x=0

x²-9x+18=0
D=(-9)²-4*1*18=81-72=9
x1=(9+3)/2=6
x2=(9-3)/2=3

Ответ: x1=0, x2=3, x3=6

Answer 2

2x(x-3)²-x²(x-3)=0
x=0
x=3
x=6