Question

5 cos^ 3α tg 3α
Помогите пожалуйста)

Answer 1

5cos³(3α)·tg(3α)=5cos³(3α)·(sin(3α)/cos(3α))=5cos²(3α)·(sin(3α)=
=5cos(3α)·(sin(3α)·cos(3α))=5cos(3α)·sin(6α)/2=(5sin6αcos3α)/2