Question

пределы пожалуйста, 10 баллов

Answer 1

$1)quad limlimits _{n to +infty} frac{2n^2+5}{6n+4n^2-7} = limlimits _{n to +infty} frac{2+5/n^2}{6/n+4-7/n^2} =frac{2}{4}=0,5\\2)quad limlimits _{n to +infty} (sqrt{n+2}-sqrt{n})= limlimits _{n to +infty} frac{(n+2)-n}{sqrt{n+2}+sqrt{n}} =\\= limlimits _{n to +infty}frac{2}{sqrt{n+2}+sqrt{n}} =[, frac{2}{+infty } , ]=0$