Question

Решите уравнения, плиииз!!
1. tgx+2=0
2. ctg2x=-√3/3
5. 3tg^2+√3tgx=0

Answer 1

1) $tg(x)=-2$
$x=- arctg(2) +picdot k$

2) $ctg (2x) = -frac{sqrt{3}}{3}$
$2x = -frac{pi}{3}+picdot k$
$x = -frac{pi}{6}+frac{pi}{2}cdot k$

3) $left(sqrt{3}tg(x)+ 1right)tg(x) =0$
$tg(x) =0$
$x=picdot k$
или
$tg(x)=-frac{1}{sqrt{3}}$
$x = -frac{pi}{6}+picdot n$