Question

log4(x-2)+log4(x-8)=1

Answer 1

log₄(x-2)+log₄(x-8)=1
log₄(x-2)(x-8)=log₄4
log₄(x²-8x-2x+16)=log₄4
x²-10x+16=4
x²-10x+12=0
D=(-10)²-4*1*12=100-48=52
x₁=(10+2√13)/2=5+√13
x₂=(10-2√13)/2=5-√13