Question

b5=61 b11=1647 b2=? b9=?

Answer 1

$b_5=b_2cdot q^3Rightarrow b_2=frac{b_5}{q^3}\b_{11}=b_9cdot q^2Rightarrow b_9=frac{b_{11}}{q^2}\b_{11}=b_5cdot q^6\1647=61cdot q^6\q^6=27\q=sqrt[6]{27}=sqrt3\q^2=3,;q^3=3sqrt3\b_2=frac{61}{3sqrt3}\b_9=frac{1647}{3}=549$