Question

решите систему уравнений y-2x=-1 2x(квадрат) - y(квадрат)=1

Answer 1

Y - 2X = - 1 --> Y = 2X - 1

2X^2 - Y^2 = 1

2X^2 - (4X^2 - 4X + 1) = 1

2X^2 - 4X^2 + 4X - 1 = 1

-2X^2 + 4X - 2 = 0

D = 16 - 4*(-2)*(-2) = 16 - 16 = 0

X = -4 / - 4 = 1

Y = 2X - 1 = 1

Ответ: Х = 1 Y = 1