Question

Помогите решить!!!!!
1.)√4x+√64x-√81x=?
2.)(5√7-√63+√14)*√7=?
3.)√12y-0,5√48y+2√108y=?

Answer 1

$1) sqrt{4x} +sqrt{64x}-sqrt{81x}=2sqrt{x}+8sqrt{x}-9sqrt{x}=sqrt{x} \ \ 2)(5sqrt{7}-sqrt{63}+sqrt{14})*sqrt{7}=(5sqrt{7}-3sqrt{7}+sqrt{14})*sqrt{7}= \ =(2sqrt{7}+sqrt{2*7})*sqrt{7}=2*7+sqrt{2*7*7} =14+7 sqrt{2} \ \ 3) sqrt{12y}-0.5sqrt{48y}+2sqrt{108y}= sqrt{4*3y}-0.5sqrt{16*3y}+2sqrt{36*3y}= \ =2sqrt{3y}-0.5*4sqrt{3y}+2*6sqrt{3y}=2sqrt{3y}-2sqrt{3y}+12sqrt{3y}= \ =12sqrt{3y}$

Answer 2

Спасибо огромное!!!!!!

Answer 3

пожалуйста)

Answer 4

=)))