Question

решите, пожалуйстааа

Answer 1

$frac{6}{a-1}- frac{10}{(a-1)^2}: frac{10}{a^2-1}- frac{2a+2}{a-1}= frac{6}{a-1}- frac{10}{(a-1)^2}* frac{(a+1)(a-1)}{10}- frac{2a+2}{a-1}= \ \= frac{6}{a-1}- frac{(a+1)}{a-1}- frac{2a+2}{a-1}= frac{6-(a+1)-(2a+2)}{a-1} =frac{6-a-1-2a-2}{a-1}= frac{-3a+3}{a-1}= \ \ = frac{-3(a-1)}{(a-1)}=-3$