Question

(корень13+корень7)^2/10+корень91

Answer 1

$dfrac{(sqrt{13}+sqrt{7})^2}{10+sqrt{91}} = dfrac{(sqrt{13})^2+2sqrt{13}cdot sqrt{7}+(sqrt{7})^2}{10+sqrt{91}} =\ \ \=dfrac{13+7+2sqrt{91}}{10+sqrt{91}} = dfrac{2(10+sqrt{91})}{10+sqrt{91}} =2$