Предмет: Физика, автор: maschakuzichkin

Проводник длиной 20 см с током силой 10 А находится
в магнитном поле, индукция которого 0,03 Тл. Направление тока
составляет с направлением индукции поля угол 60º. Определить
силу, действующую на проводник.

Ответы

Автор ответа: Андрей12121
0
Fа=B*I*L*sin(A)
L=0.2 м
Fa=0.05 Н
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