Question

Разложите на множители:
a²+ab+ax+bx
x+y-x²-xy
6m-12-2n+mn
4ab²+5ab+a

Answer 1

$a^{2} +ab+ax+bx=a(a+b)+x(a+b)=(a+b)(x+b)$
$x+y- x^{2} -xy=x+y-x(x+y)=(x+y)(1-x)$
$6m-12-2n+mn=6(m-2)+n(-2+m)=6(m-2)+n(m-2)=$
$=(m-2)(6+n)$
$4ab^{2}+5ab+a=a(4b^{2}+4b+b+1)=a(4b(b+1)+(b+1))=$
$=a(b+1)(4b+1)$