Question

m(B2O3)=17грамм V(H2O)300 мл найдите Cm(B2O3) даю 5 баллов

Answer 1

M(B2O3)=11*2+16*3=70g/mol
n(B2O3)=17g/70g/mol=0.24mol
0.24mol-300g(H2O)
xmol     -1000g(H2O)
x=0.24*1000/300=0.8mol
Cm=0.8M