Question

помогите решить номер 162 (2, 4)

Answer 1

$(6-n)^{2}-(n+6)^{2}$ =36-12n+n²-(n²+12n+36)=36-12n+n²-n²-12n-36=-24n
(2p-q)²-(q+2p)²=4p²-4pq+q²-q²-4pq-4p²=-8pq