Question

x^2-6x+9 дробная чета x^2-3x

Answer 1

$frac{x^2-6x+9}{x^2-3x}= frac{x^2-2*3*x+3^2}{x(x-3)}= frac{(x-3)^2}{x(x-3)}= frac{x-3}{x}$