Question

2 sin^2x-5sinx•cosx=3 помогите решить

Answer 1

5sin^2х-3,5sincosx+2cos^2 х-3sin^2x-3cos^2x=0
2sin^2x-cos^2x-3,5sinxcosx=0 
2tg^x-3,5tgx-1=0
tgx=1/4 
tgx=2
x=arctg2+Пk
x=arctg(1/4)+Пk