Предмет: Физика, автор: Lera90fhg

опредилите вес мальчика, движущегося в лифте в низ с ускорением 0,15 м/с 2.Масса мальчика 40 кг

Ответы

Автор ответа: 21fizika

На мальчика действует сила тяжести вниз и сила упругости пола (реакция опоры) вверх: mg-Fупр=ma, P численно =Fупр=m(g-a)=40*(9,8-0,15)=
40*9,65=4*96,5=386 H.

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