Question

решите параметр срочно

Answer 1

$frac{x-3}{p+1}=frac{2x-p-1}{x+3}\x^2-9=(2x-p-1)(p+1)\x^2-9=2px-p^2-p+2x-p-1\x^2-9=2px-p^2-2p+2x-1\x^2-9=-(p+1)^2+2x(p+1)\(p+1)^2-2x(p+1)+x^2-9=0|p+1=a\a^2-2xa+x^2-9\a_{1,2}=frac{x^+_-sqrt{x^2-x^2+9}}{1}\a_1=x+3 ;a_2=x-3\p+1=x+3 ; p+1=x-3\p=x+2 p=x-4$

$frac{x+2}{p-4}=frac{2x-p+4}{x-2}\x^2-4=(2x-(p-4))(p-4)\x^2-4=2x(p-4)-(p-4)^2\(p-4)^2-2x(p-4)+x^2-4=0|p-4=a\a^2-2xa+x^2-4\a_{1,2}=frac{x^+_-sqrt{x^2-x^2+4}}{1}\a_1=x+2 ;a_2=x-2\p-4=x+2 ;p-4=x-2\p=x+6 ;p=x+2$