Question

найдите корень уравнения $(frac{1}{4})^{12-4x}=16$

Answer 1

$[begin{array}{l} {left( {frac{1}{4}} right)^{12 - 4x}} = 16\ {left( {frac{1}{4}} right)^{12 - 4x}} = {left( {frac{1}{4}} right)^{ - 2}}\ 12 - 4x = - 2\ x = 3.5 end{array}]$