Question

Помогите с решением
1)Arccos(-√2/2)+arcsin(-1)
2)arctg1+arcctg√3

Answer 1

1) arccos(-√2/2)+arcsin(-1)=3π/4-π/2=(3π-2π)/4=π/4
2)arctg1+arcctg√3=π/4+π/6=(3π+2π)/12=5π/12