Question

Помогите решить уравнение Sin(-x) = 1

Answer 1

-sinx=1
-1(-sinx)=-1*1
sinx=-1
sinx=-1
sin(π-x)=-1
x=arcsin(-1)
π-x=arcsin(-1)
x=-π/2
π-x=-π/2
x=-π/2+2π, κ∈z
π-x=-π/2+2π,κ∈z
x=-π/2+2π,κ∈z
x=3π/2-2κπ,κ∈z
x=-π/2+2π,κ∈z
x=3π/2+2κπ,k∈z