Question

x^3-6x^2-4x+24=0 Помогите решить.

Answer 1

x^3-6x^2-4x+24=0

x^2(x-6)-4(x-6)=0

(x^2-4) (x-6) = 0

x^2-4=0                        x-6=0

x^2=4                            x=6

x1 = 2; x2=-2

 

 

ответ: x=-2; x=2; x=6

 

 

 

 

 

Answer 2

x^3-6x^2-4x+24=0

(x-6)*(x-2)*(x+2)=0

(x-6)=0
x=6
 

(x-2)=0
x=2
 

(x+2)=0
x=-2