Предмет: Физика, автор: Icitittiyi

определите, сколько энергии потребуется сообщить 20 г воды, взятой при температуре 0 , для того чтобы нагреть её до температуры кипения и испарить

Ответы

Автор ответа: кролик99
0
на нагрев воды нужно количество теплоты: Q=cm(t2-t1)
Q=4200*0,02*100=8400 Дж
на испарение требуется:
Q=Lm
Q=0,02*2,3*1000000=0,046*1000000=46000 Дж
итого в сумме имеем: 46000+8400=54400 Дж
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