Предмет: Алгебра, автор: MissAC

Вычислите:

1.75 - 1 11/17* 51/56+ 0.75:(4- 1.2*(3.25- 1 1/12+ 6 2/3: 20))

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                                (-0,1) в квадрате

Ответы

Автор ответа: ConsuLX
0

(1.75-1 11//17*51//56+0.75:(4-1.2*(3.25-1 1//12+6 2//3:20)))/(-0,1)^2=(1.75-28//17*51//56+0.75:(4-1.2*(3.25-1 1//12+6 2//3:20)))/(-0.1)^2=(1.75-1.5+0.75:(4-1.2*(3.25-1 1//12+6 2//3:20)))/(-0.1)^2=(0.25+0.75:(4-1.2*(3.25-1 1//12+6 2//3:20)))/(-0.1)^2=(0.25+0.75:(4-1.2*(13//6+6 2//3:20)))/(-0.1)^2=(0.25+0.75:(4-1.2*(13//6+20//3:20)))/(-0.1)^2=(0.25+0.75:(4-1.2*(13//6+1//3)))/(-0.1)^2=(0.25+0.75:(4-1.2*2.5))/(-0.1)^2=(0.25+0.75:(4-3))/(-0.1)^2=(0.25+0.75)/(-0.1)^2=1/(-0.1)^2=1/0.01=100

// - черта дроби 

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