Question

даю 79 балов (34+12-38):(1 512-916+1 13)+(2,48:0,4-3,2):(4,19+2,7*0,3)=

Answer 1

(34+12-38):(1 512-916+1 13)+(2,48:0,4-3,2):(4,19+2,7*0,3)

(34+12-38) = 6/8 + 4/8 - 3/8 = 7/8
(1 512-916+1 13) = 17/12 - 9/16 + 4/3 = 68/48 - 27/48 + 64/48 = 105/48
(2,48:0,4-3,2) = 6,2 - 3,2 = 3
(4,19+2,7*0,3) = 4,19 + 0,81 = 5

7/8 : 105/48 + 3 : 5 = 42/105 + 3/5 = 42/105 + 63/105 = 105/105 = 1

(34+12-38):(1 512-916+1 13)+(2,48:0,4-3,2):(4,19+2,7*0,3) = 1