Question

HEEEEELLLLLPPPPPPPPPPPPPPP

Answer 1

Ответ в приложении ₩¥£€₩¥£€₩¥£€₩¥£€

Answer 2

1
y=sin(πx²),x0=1
y(1)=sinπ=0
y`=2πx*cosπx²
y`(1)=2π*cosπ=2π*(-1)=-2π
y=0-2π(x-1)=2π(1-x)
2
y`=2tg(x/2)*1/cos²(x/2) *1/2=tg(x/2)/cos²(x/2)=sin(x/2)/cos³(x/2)