Question

найдите корни квадратного трехчлена:
а) 2х²+9х+4

б) х²+14х+48

Answer 1

$2x^2+9x+4\2x^2+9x+4=0\D=81-32=49=7^2,D textgreater 0\x_{1,2}= frac{-9б7}{4} = |{ {{-4} atop {-0.5}} right. \OTBET:-4;-0.5\\x^2+14x+48\x^2+14x+48=0\D_1=( frac{14}{2})^2 -48=49-48=1,D textgreater 0\x_{1,2}=-7б1=|{ {{-8} atop {-6}} right. \OTBET:-8;-6$

Answer 2

Спасибо.