Question

(4^(4n-2))*(0.2^-2n)/(80^(2n-1)

Answer 1

Исходное:
(4^(4n-2))*(0.2^-2n)/(80^(2n-1))
Упрощаем:
(25n*2^(8n-4))/(2^(8n-4)*5^(2n-1))

Сокращаем:
(25n)/(5^(2n-1))

Считаем:

n*5^(3-2n)

Answer 2

(4^(4n-2))*(0.2^-2n)/(80^(2n-1))=(16^2n/16*5^2n)/(80^2n/80)=(80^2n)/16*80/(80^2n)=

=400n*80/(80^2*n)=32000n/(6400n)=5n/n=5