Question

4x^2+x/3-x^2+17/9=5x-1/6

Answer 1

$frac{4x^2+x}{3}- frac{x^2+17}{9}= frac{5x-1}{6} |*18\6(4x^2+x)-2(x^2+17)=3(5x-1)\24x^2+6x-2x^2-34-15x+3=0\22x^2-9x-31=0\D=b^2-4ac=81+2728=2809,D textgreater 0\x_{1.2}= frac{9б sqrt{2809} }{44} =|{ {{-1} atop { frac{31}{22} }} right. \OTBET:-1; frac{31}{22}$