Question

найти число x : log5 x = log 5 c - 2log5 b + log 5 a

Answer 1

$log_5x=log_5c-2log_5b+log_5a$
$log_5x=log_5c-log_5b^2+log_5a$
$log_5x=log_5{ frac{c}{b^2} }+log_5a$
$log_5x=log_5{ frac{c}{b^2}*a }$
$x= frac{c*a}{b^2}$