Question

(log(2) 56 + 21log(2) 12- log(2) 63)* 10^(1+lg2)

Answer 1

$(log_2 56 + 2log_2 12- log_2 63)* 10^{1+lg2}=\ (log_2(56*12^{2}:63))*10*10^{lg2}=\ log_2128*10*2=7*20=140$