Question

$log_frac{1}{3} (4x-5) = -3$

Answer 1

$log_ frac{1}{3} (4x-5)=log_ frac{1}{3} (frac{1}{3})^{-3} log_ frac{1}{3} (4x-5)=log_ frac{1}{3} 27 4x-5=27 4x=32 x=8$