Question

Помогите!!
Найдите сумму целых корней уравнения:
(x^+11x+28)*(6x-12)=0

Answer 1

x^2 + 11x + 28 = 0
D = 121 - 112 = 9 = 3^2
x1 = (-11 + 3)/2 = -4
x2 = (-11-3)/2 = -7

6x-12 = 0
x3 = 2

x1 + x2 + x3 =  -4 -7 + 2 = -9