Question

Тригонометрия 5-6 задание

Answer 1

5
a)cosπ/6*tg45-sinπ/3*ctg45=1/2*1-1/2*1=0
b)(sin3π/2-cos0)/(tg0+ctgπ/4)=(-1-1)/(0+1)=-2/1=-2
6
a)1+tg²a-tg²a-sin²b=1-sin²b=cos²b
b)(sin²a/cos²a - sin²a)*(1+ctg²a-1)=sin²a(1-cos²a)/cos²a *cos²a/sin²a=
=1-cos²a=sin²a