Question

Помогите решить уравнения
1) X^2+3x=0
2) x^2-4x-5=0

Answer 1

1)X^2+3x=0 X(x+3)=0 X=0 X+3=o X=-3 2)x^2-4x-5=0 D=(-4)^2-4*1*(-5)=36 x1,2 = (4+-√36) / 2 = (4+-6) / 2 = 2+-3 x1 = 2-3 = -1, x2 = 2+3 = 5.