Question

решите уравнение (3x+4)^2-(3x-1)*(1+3x)=65

Answer 1

9x^2+24x+16-9x^2+1=65
24x=48
x=2

Answer 2

(3x+4)^2-(9x^2-1)=65

9x^2+24x+16-9x^2+1-65=0

24x-48=0

24x=48

x=48/24

x=2

ответ:2