Question

номер 109 (1 и 4 ) пожалуйста

Answer 1

108.1$sqrt[3]{(7- sqrt{22} )(7+ sqrt{22}) } = sqrt[3]{49-22} = sqrt[3]{27} =3$
108.2
1/(4+2√3)+1/(4-2√3)=(4-2√3+4+2√3)/(16-12)=8/4=2
109.1
2*√(3/2*2/3)-6√(3/8*2/3)+8√(3/2*2/3)=2√1-6√1/4+8√1=2+6/2-8=10-3=7
109.4
$sqrt[4]{125/27*5/3} - sqrt[4]{375*5/3} - sqrt[4]{1/135*5/3} =$$sqrt[4]{625/81} - sqrt[4]{625} - sqrt[4]{1/81} =5/3-5-1/3=4/3-5=-11/3$