Question

1) (1/4)^x=(1/5)^x
2)0,3^6x-1-0,3^6x>=0,7
Помогите решить ))))

Answer 1

$displaystyle frac{1}{4}^x= frac{1}{5}^x$

т.к. 1/4≠1/5

то х=0

$displaystyle 11^{-7x+1} leq 121^{-2x-10} 11^{-7x+1} leq 11^{-4x-20} -7x+1 leq -4x-20 -3x leq -21 x geq 7$


$displaystyle 0.09^{5x-1} textless 0.3{x+7} 0.03^{10x-2} textless 0.3^{x+7}$

$displaystyle 10x-2 textgreater x+7$

$displaystyle 9x textgreater 9$
$displaystyle x textgreater 1$



$displaystyle 0,3^{6x-1}-0.3^{6x} geq 0.7 0.3^{6x}(1/0.3-1) geq 0.7 0.3^{6x}(0.7/0.3) geq 0.7 0.3^{6x} geq 0.3 6x leq 1 x leq 1/6$