Question

Решите систему неравенств под буквой Б

Answer 1

$left { {{x^2-x-12 textless 0,} atop {x^2-4x+3 geq 0;}} right. left { {{(x+3)(x-4) textless 0,} atop {(x-1)(x-3)geq 0;}} right. left { {{-3 textless x textless 4,} atop {left { {{x leq 1,} atop {x geq 3;}} right.}} right. left [ {{-3 textless x leq 1,} atop {3 leq x textless 4;}} right. \ xin(-3;1]cup[3;4).$

$left { {{x^2+x-2 geq 0,} atop {frac{x+2}{x-4}leq 0}} right. left { begin{array}{ccc}(x+2)(x-1) geq 0,\x-4 neq 0,\(x+2)(x-4) leq 0;end{array}right. left { begin{array}{ccc} left [ {{x leq -2,} atop {x geq 1,}} right. \x neq 4,\-2 leq x leq 4;end{array}right. left [ {{x=-2,} atop {1 leq x textless 4;}} right. \ xin{-2}cup[1;4).$

$left { {{|x| leq 2,} atop {x^2-x-6 geq 0;}} right. left { {{-2 leq x leq 2,} atop {(x+2)(x-3) geq 0;}} right. left { {{-2 leq x leq 2,} atop {(x+2)(x-3) geq 0;}} right. left { {{-2 leq x leq 2,} atop { left [ {{x leq -2,} atop {x geq 3;}} right. }} right. \ x=-2.$

Answer 2

спасибо Вам большое!