Предмет: Химия, автор: Daria2626

вычислите объем и массу хлора затраченного на реакцию с 23 г металлического натрия

Ответы

Автор ответа: Fogus

0

2Na + Cl₂ = 2NaCl
m=23г n=0,5
n=23/23=1 V=22,4*0,5=11,2
m=0,5*71=35,5г

Ответ: Cl₂ 11,2дм³, 35,5г

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