Question

1) (х+6)²=(15-х)²
2)(х-3)÷$frac{ x^{2} -6x+9}{x+3}$

Answer 1

1) (х+6)²=(15-х)²
(х+6)(х+6)=(15-х)(15-х)
х²+6х+6х+36=225-15х-15х+х²
х²+12х+36-225+30х-х²=0
42х-189=0
42х=189
х=4.5

2) (х-3):((х²-6х+9)/(х+3))=
=((х-3)(х+3))/(х²-6х+9)=
=((х-3)(х+3))/((х-3)(х-3))=
=(х+3)/(х-3)