Question

16x^3 - 32x^2 - x + 2=0

Answer 1

$displaystyle 16x^3 -32x^2-x+2=0\underline{16x^2 }cdot x-underline{16x^2 }cdot 2-1cdot (x)-1cdot (-2)=0\16x^2underline{(x-2)} -1cdot underline{(x-2)} =0\(16x^2-1)(x-2)=0\\begin{bmatrix}16x^2-1=0\x-2=0;;end{matrix} qquad begin{bmatrix}x^2=frac1{16} \x=2;,;end{matrix} qquad begin{bmatrix}x=pm frac14 \x=2;,end{matrix}$

Ответ: x = { -0,25 ; 0,25 ; 2 }.