Предмет: Математика, автор: newworld1

функция определена на промежутке (-4;6). на рисунке изображен график ее производной. найдите число касательных к графику функции, которые наклонены под углом 50 градусов к положительному направлению оси абсцисс

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Автор ответа: andrisd

Чтобы узнать количество касательных наклоненных под углом 50°, надо найти tg50°
tg50°=1.19
Чертим график у=1.19
он пересекает график производной 7 раз. Значит касательных к графику 7.

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