Question

решите неравенство: 1)2x^2-5x+2<0
2)6x^2+x-1>0

Answer 1

1)2x^2 - 5x +2x<0
2x^2 -5x +2x = 0
a=2 b= -5 c = 2
D = b^2 -4ac = 25 - 4 * 2 * 2 = 25 - 16 = 9
√ D = 3
x = b+- √D/2a
x1 = -5 + 3 / 2 *2 = -2 /4 = - 0.5
x2 = -5 - 3/2*2 = -8 / 4 = -2
Ответ; ( -2 ; -0.5)
2)6x^2 +x -1 > 0
2х^2 + x - 1 = 0
a= 2 b = 1 c = -1
D = b^2-4ac = 1 + 4 * 2 * (-1) = 9
√D =3
x= b +- √D / 2a
x1= 1 + 3 / 2*2 = 4/4 = 1
x2= 1-3 / 2*2 = -2 /4 = -0.5
Ответ: х c ( - бесконечность ; -0.5 ) U ( 1 ; + бесконечность)