Question

(2x-3)^2-4x^2=0 найдите корень уравнения

Answer 1

(2x-3)^2-4x^2=0
(4х^2-12x+9)-4x^2=0
12x=9
x=0.75

Answer 2

$(2x-3)^2-4x^2=0\(2x-3-2x)(2x-3+2x)=0\4x-3=0\x=frac{3}{4}$