Question

$2n^{k}+3n=k!$

Answer 1

k≥4k≥4
k!k! : 2m2m
m>k/2m>k/2
2nk−1−32nk−1−3
n>2k/2n>2k/2
2nk−3n>nk>2k2/2>k!.2nk−3n>nk>2k2/2>k!
k<4k<4.