Question

√500 √72 √90 √20  задание вынести множитель

Answer 1

$sqrt{500}=sqrt{100*5}=sqrt{100}*sqrt5=10sqrt5 \ \ sqrt{72}=sqrt{36*2}=sqrt{36}*sqrt2=6sqrt2 \ \ sqrt{90}=sqrt{9*10}=sqrt{9}*sqrt{10}=3sqrt{10} \ \ sqrt{20}=sqrt{4*5}=sqrt{4}*sqrt5=2sqrt5$